Cpp Program to check whether a number is Armstrong number or not

This a Cpp program to check whether a given number is armstrong or not . Generally a number is said to be an armstrong number if the cubes of the digits is equal to its original number . For Example : 153 is an armstrong number as 1³ + 5³ + 3³ = 153 whereas 234 is not an armstrong number as 2³+ 3³+ 4³ is not equal to 234.

PROGRAM :

#include <iostream>

using namespace std;

int main()
{
    int n,copy_num,remainder,sum = 0;
    cout << "Enter a number : \t" ;
    cin >> n;
    copy_num = n;
    
    while(n)
    {
        remainder = n%10;
        sum=sum+remainder*remainder*remainder;
        n=n/10;
    }
    if(copy_num == sum)
    cout << copy_num << " is an ARMSTRONG number" << endl;
    else
        cout << copy_num << " is an  not an armstrong number" << endl;
    return 0;
}

OUTPUT :

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