This a Java program to check whether a given number is armstrong or not .
Generally a number is said to be an armstrong number if the cubes of the digits is equal to its original number .
For Example : 153 is an armstrong number as 1³ + 5³ + 3³ = 153 whereas 234 is not an armstrong number as 2³+ 3³+ 4³ is not equal to 234.
PROGRAM :
Related Programs :
Palindrome number in C
Palindrome number in Cpp
Reverse of a number in Java
Palindrome number in Java
Reverse of a number in C
Reverse Of a number in Cpp
Armstrong number in C
Armstrong number in Cpp
Generally a number is said to be an armstrong number if the cubes of the digits is equal to its original number .
For Example : 153 is an armstrong number as 1³ + 5³ + 3³ = 153 whereas 234 is not an armstrong number as 2³+ 3³+ 4³ is not equal to 234.
PROGRAM :
package codingcorner.in; import java.util.Scanner; public class Armstrong { public static void main(String[] args) { int number, num, sum = 0, remainder; Scanner scan = new Scanner(System.in); System.out.println("Enter any number :\t"); number = scan.nextInt(); scan.close(); num = number; while (num != 0) { remainder = num % 10; sum = sum + remainder * remainder * remainder; num = num / 10; } if (number == sum) System.out.println(number + " is an Armstrong number"); else System.out.println(number + " is an not an Armstrong number"); } }OUTPUT :
Related Programs :
Palindrome number in C
Palindrome number in Cpp
Reverse of a number in Java
Palindrome number in Java
Reverse of a number in C
Reverse Of a number in Cpp
Armstrong number in C
Armstrong number in Cpp
No comments:
Post a Comment